\(R_{CB}=R_{23}=\frac{10.15}{10+15}=6\Omega\)
\(\Rightarrow R_{tđ}=R_1+R_{CB}=4+6=10\Omega\)
\(I_{CB}=I_1=\frac{U_{CB}}{R_{CB}}=\frac{5,4}{6}=0,9A\)
\(I_2=\frac{U_{CB}}{R_2}=\frac{5,4}{10}=0,54A\)
\(I_3=\frac{U_{CB}}{R_3}=\frac{5,4}{15}=0,36A\)
\(I=0,9A\)