\(MgCO_3+2HCl\rightarrow MgCl_2+H_2O+CO_2\left(1\right)\)
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\left(2\right)\)
Ta có:
\(n_{khi}=\frac{1,288}{22,4}=0,0575\left(mol\right)\)
\(n_{HCl}=2n_{khi}=0,115\left(mol\right)\)
\(\Rightarrow V_{HCl}=\frac{0,115}{0,46}=0,25\left(l\right)\)