Question

cho góc aHy= 1400. Tia Hm nằm giữa 2 tia Ha và Hy sao cho góc mHa= 1/4 góc aHy. Tính góc mHa, mHy (Các bn ơi giúp mk vs mk đag cần gấp)

Answer 1

giúp mk vs đag cần gấp

Answer 2

\(\left\{{}\begin{matrix}H_1=\dfrac{1}{4}\left(H_1+H_2\right)\\H_1+H_2=140^0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}H_1=\dfrac{140}{4}=25^0\\H_2=140^0-H_1=140^0-25^0=115^0\end{matrix}\right.\)

Answer 3

\(\left\{{}\begin{matrix}H_1=\dfrac{1}{4}\left(H_1+H_2\right)=\dfrac{1}{4}.140^0=35^0\\H_2=\left(H_1+H_2\right)-H_1=140^0-35^0=105^0\end{matrix}\right.\)