2Cu + O2 \(\underrightarrow{to}\) 2CuO (1)
CuO + 2HCl → CuCl2 + H2O (2)
\(n_{H_2O}=\frac{3,6}{18}=0,2\left(mol\right)\)
Theo PT: \(n_{CuO}=n_{H_2O}=0,2\left(mol\right)\)
Theo Pt1: \(n_{Cu}=n_{CuO}=0,2\left(mol\right)\)
\(\Rightarrow m_{Cu}=0,2\times64=12,8\left(g\right)\)
Theo Pt2: \(n_{HCl}=2n_{H_2O}=2\times0,2=0,4\left(mol\right)\)
\(\Rightarrow m_{HCl}=0,4\times36,5=14,6\left(g\right)\)