Ta có nH2 = \(\dfrac{4,48}{22,4}\) = 0,2 ( mol )
Mg + 2HCl \(\rightarrow\) MgCl2 + H2
x..........2x..........x............x
Zn + 2HCl \(\rightarrow\) ZnCl2 + H2
y.........2y..............y........y
=> \(\left\{{}\begin{matrix}24x+65y=8,9\\x+y=0,2\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x=0,1\\y=0,1\end{matrix}\right.\)
=> mZn = 65 . 0,1 = 6,5 ( gam )
=> %mZn = \(\dfrac{6,5}{8,9}\times100\approx73\%\)
=> %mMg = 100 - 73 = 27 %
Ta có Mdung dịch = Mtham gia - MH2
= 200 + 8,9 - ( 0,1 + 0,1 ) . 2
= 208,5 ( gam )
=> mMgCl2 = 95 . 0,1 = 9,5 ( gam )
=> C%MgCl2 = \(\dfrac{9,5}{208,5}\times100\approx4,6\%\)
=> mZnCl2 = 136 . 0,1 = 13,6 ( gam )
=> C%ZnCl2 = \(\dfrac{13,6}{208,5}\times100\approx6,5\%\)
