a) PTHH: \(2Mg+O_2-^{t^o}\rightarrow2MgO\)
\(2Ca+O_2-^{t^o}\rightarrow2CaO\)
b) Bảo toàn khối lượng: mKL+mOxi=mOxit
=> mOxi=mOxit-mKL=13,6-8,8=4,8g
c) \(n_{O_2}=\frac{4,8}{32}=0,15\left(mol\right)\)
\(\Rightarrow V_{O_2}=0,15.22,4=3,36\left(l\right)\)