Gọi CTC là FexOy
\(n_{Fe}=0,1\left(mol\right)\)
\(Fe_xO_y+yCO-t^0->xFe+yCO_2\uparrow\)
0,1/x.....................................0,1
\(M_{Fe_xO_y}=56x+16y=\dfrac{8}{\dfrac{0,1}{x}}\)
\(\Leftrightarrow56x+16y=80x\)
\(\Leftrightarrow16y=24x\)
\(\Leftrightarrow\dfrac{x}{y}=\dfrac{16}{24}=\dfrac{2}{3}\Rightarrow\left\{{}\begin{matrix}x=2\\y=3\end{matrix}\right.\)
CTHH : Fe2O3