a.Fe2O3+3H2SO4->Fe2(SO4)3+3H2O
nFe2O3=\(\dfrac{4,8}{160}=0,03\left(mol\right)\)
=>nFe2(SO4)3=0,03(mol)=>mFe2(SO4)3=0,03*400=12(g)
b.nH2SO4=0,03*3=0,09(mol)
=>CMH2SO4=\(\dfrac{0,09}{0,5}=0,18\left(mol\right)\)
c.H2SO4+Zn->ZnSO4+H2
nZn=\(\dfrac{45,5}{65}=0,7\left(mol\right)\)
Xét tỉ lệ:\(\dfrac{nH2SO4}{nH2SO4pt}=\dfrac{0,09}{1}< \dfrac{nZn}{nZnpt}=\dfrac{0,7}{1}\)
=>Zn dư. Sản phẩm rính theo H2SO4.
nH2=0,09(mol)
=>VH2(đktc)=0,09*22,4=2,016(l)