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Theo đề bài, ta có: \(m_{Na2CO3}=450.11,78\%=53,01\left(g\right)\)
\(\Rightarrow n_{Na2CO3}=\dfrac{53,01}{106}=\dfrac{5301}{10600}\left(mol\right)\)
PTHH: \(Na_2CO_3+2HCl\rightarrow2NaCl+CO_2\uparrow+H_2O\)
pư.............\(\dfrac{5301}{10600}\)........\(\dfrac{5301}{5300}\).......\(\dfrac{5301}{5300}\)........\(\dfrac{5301}{10600}\).....\(\dfrac{5301}{10600}\) (mol)
a) \(V_{CO2}=22,4.\dfrac{5301}{10600}\approx11,2\left(l\right)\)
b) \(M_{HCl}=1+35,5=36,5\left(\dfrac{g}{mol}\right)\)
c) \(C\%_{NaCl}=\dfrac{\dfrac{5301}{5300}.58,5}{450+200-44.\dfrac{5301}{10600}}.100\%\approx9,32\%\)
Vậy.............