PTHH: \(Mg+2HCl\rightarrow MgCl_2+H_2\)
Ta có: \(n_{Mg}=\frac{3,6}{24}=0,15\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}n_{MgCl_2}=0,15mol=n_{H_2}\\\Sigma_{n_{HCl}}=0,345mol\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}m_{MgCl_2}=0,15\cdot95=14,25\left(g\right)\\m_{H_2}=0,15\cdot2=0,3\left(g\right)\\m_{ddHCl}=\frac{0,345\cdot36,5}{25\%}=50,37\left(g\right)\end{matrix}\right.\)
Mặt khác: \(m_{dd}=m_{Mg}+m_{ddHCl}-m_{H_2}=53,67\left(g\right)\)
\(\Rightarrow C\%_{Muối}=\frac{14,25}{53,67}\cdot100\approx26,55\%\)
