PTHH: \(Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\)
Ta có: \(n_{Zn}=\frac{15}{65}=\frac{3}{13}\left(mol\right)\) \(\Rightarrow n_{H_2}=\frac{3}{13}\left(mol\right)\)
\(\Rightarrow n_{Fe}=\frac{2}{13}mol\) \(\Rightarrow m_{Fe}=\frac{2}{13}\cdot56\approx8,62\left(g\right)\)