C2H4 + H2O => (140oC,H2SO4đ) C2H5OH
A là C2H5OH
C2H5OH + Na => C2H5ONa + 1/2 H2
15C2H5OH + 5Na2CO3 => 10C2H5COONa + 5CO2 + 2H2O
nC2H4 = V/22.4 = 1.12/22.4 = 0.05 (mol0
==> nC2H5OH = 0.05 (mol) ==> mC2H5OH = 2.3 (g)
H%=60% => n pứ = 0.03 (mol)
mC2H5OH dư = 0.02 x 46 = 0.92 (g)
mC2H5ONa = 0.03 x 68 = 2.04 (g)
=> mB = 0.92 + 2.04 = 2.96 (g)