Na2CO3+H2SO4------->Na2CO4+H2O+CO2
b) n Na2CO3=10,6/106=0,1(mol)
Theo pthh
n CO2=n Na2CO3=0,1(mol)
V CO2=0,1.22,4=2,24(l)
c) Theo pthh
n H2SO4=n Na2CO3=0,1(mol)
m H2SO4=0,1.98=9,8(g)
m dd H2SO4=9,8.100/9,8=100(g)
d) m dd sau pư=10,6+100-4,4=106,2(g)
m Na2SO4=0,1.142=14,2(g)
C% Na2SO4=14,2./106,2.100%=13,37%
Chúc bạn hcoj tốt