a.Fe+H2SO4---->FeSO4+h2
b. nH2=0,15 mol
Fe+H2SO4---->FeSO4+h2
0,15<--0,15<---------------0,15
mFe=0,15.56=8,4g
c. n h2so4=0,15 mol
C M=0,15/0,6=0,25 M
pt Fe+H2SO4---->FeSO4+H2
nH2=3,36/22,4=0,15 mol
theo pt nFe=nH2=0,15 mol =>mFe=0,15*56=8,4 g
theo pt n H2SO4=nH2=0,15 MOL =>Cm H2SO4=0,15:0,6=0,25M