\(L=1700.10^3\left(\overset{o}{A}\right)\)
\(\Rightarrow N=\dfrac{2L}{3,4}=1000.10^3\left(nu\right)\)
Theo bài và theo NTBS ta có hệ: \(\left\{{}\begin{matrix}T+X=500.10^3\\T-X=100.10^3\end{matrix}\right.\rightarrow\left\{{}\begin{matrix}T=A=300.10^3\left(nu\right)\\X=G=200.10^3\left(nu\right)\end{matrix}\right.\)