\(V_{O_2}=\frac{V_{KK}}{5}=\frac{28}{5}=5,6\left(l\right)\Rightarrow n_{O_2}=0,25\left(mol\right)\)
\(n_{CH_4}=\frac{2,24}{22,4}=0,1\left(mol\right)\)
\(PTHH:CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)
(mol)_____0,1____0,2___0,1_____0,2_
Tỉ lệ: \(\frac{0,1}{1}< \frac{0,25}{2}\rightarrow O_2\) dư \(0,25-0,2=0,05\left(mol\right)\)
\(V_{O_2\cdot du}=22,4.0,05=1,12\left(l\right)\)
\(V_{CO_2}=0,1.22,4=2,24\left(l\right)\)
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