\(n_{H_2SO_4}=\dfrac{250.20\%}{98.1005}\approx0,51\left(mol\right)\)
\(m_{H_2SO_4}=0,51.98=49,98\left(g\right)\)
\(m_{dd\left(bd\right)}=\dfrac{49,98.100\%}{74\%}=67,54\left(g\right)\)
\(V_{dd\left(bd\right)}=\dfrac{67,54}{1,664}\approx40,58\left(ml\right)\)