CH3COOH + NaOH => (to) CH3COONa + H2O
Ta có: C%ddNaOH = 10%, mdd NaOH = 200 (g)
Theo công thức C% = mctx100/mdd
Ta suy ra: mNaOH = 20 (g)
=> nNaOH = m/M = 20/40 = 0.5 (mol)
Theo phương trình hh, ta có: nCH3COOH=nNaOH=0.5 (mol)
mCH3COOH =n.M = 0.5x60 = 30 (g)
mdd CH3COOH = 30x100/6 = 500 (g)
Vdd CH3COOH = m/D = 500/1.08 xấp xỉ 462,96 (ml)