Đổi 20l = 20000l
\(V_{C_2H_5OH}=\dfrac{20000.46}{100}=9200\left(ml\right)\\ m_{C_2H_5OH}=9200.0,8=7360\left(g\right)\\ n_{C_2H_5OH}=\dfrac{7360}{46}=160\left(mol\right)\)
PTHH:
C6H12O6 --men rượu--> 2C2H5OH + 2CO2
80<----------------------------160
C6H10O5 + H2O ---> C6H12O6
80<----------------------80
\(\Rightarrow m_{tinh.bột}=\dfrac{80.162}{50\%.60\%}=43200\left(g\right)\)