Bài 1:
Ta có: \(n_{HCl}=1,5\cdot0,08=0,12\left(mol\right)\) \(\Rightarrow V_{HCl\left(2M\right)}=\dfrac{0,12}{2}=0,06\left(l\right)=60\left(ml\right)\)
Bài 2:
PTHH: \(2Al+6HCl\rightarrow2AlCl_3+3H_2\uparrow\)
Ta có: \(n_{HCl}=2,5\cdot2=5\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}n_{Al}=\dfrac{5}{3}\left(mol\right)\\n_{H_2}=2,5\left(mol\right)\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}m_{Al}=\dfrac{5}{3}\cdot27=45\left(g\right)\\V_{H_2}=2,5\cdot22,4=56\left(l\right)\end{matrix}\right.\)