Bài 1 R1=\(p\dfrac{l1}{S1}\) (1)
R2=\(p.\dfrac{l2}{R2}\) (2)
Lấy 1: 2 ta có \(\dfrac{1}{16}=\dfrac{l1S2}{l2S1}=\dfrac{20.4.10^{-6}}{l2.4.10^{-6}}=>l2=320m\)
Bài 2 Ta có V=\(\dfrac{m}{D}=\dfrac{0,9}{8690}=\dfrac{9}{86900}=S.l=\dfrac{1}{1000000}.l=>l\sim103,6m\)
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