Ta co : Mxo2/32=1,375=>Mxo2=44
Ta lai co : X + 16.2 = 44 => X = 12 . Vay cthh cua khi la CO2
\(M_A=d_{A/O_2}.M_{O_2}=1,375.32=44\left(g/mol\right)\)
Ta có: \(XO_2=44\)
\(\Leftrightarrow X+32=44\)
\(\Leftrightarrow X=44-32\)
\(\Leftrightarrow X=12\)
\(\Rightarrow\) X là cacbon
\(\Rightarrow CTHH:CO_2\)