\(a,n_{Al}=0,5.2=1(mol)\Rightarrow m_{Al}=1.27=27(g)\\ n_{O}=0,5.3=1,5(mol)\Rightarrow m_O=1,5.16=24(g)\\ b,n_{CO_2}=\dfrac{2,2}{44}=0,05(mol)\\ \Rightarrow \begin{cases} n_C=0,05(mol)\Rightarrow m_C=0,05.12=0,6(g)\\ n_O=0,05.2=0,1(mol)\Rightarrow m_O=0,1.16=1,6(g) \end{cases}\)