a) ( x - 1 )2 -1 + x = 0
<=> x2 - 2x +1 - 1 + x = 0
<=> x2 - x = 0
=>\(\left[\begin{array}{nghiempt}x=0\\x-1=0\Rightarrow x=1\end{array}\right.\)
b) ( x - 1 )4 + 8 - 8x = 0
<=> ( x - 1 )4 - 8( x - 1 ) = 0
<=> ( x - 1 ) ( ( x - 1 )3 - 8 ) = 0
\(\left[\begin{array}{nghiempt}x-1=0\Rightarrow x=1\\\left(x-1\right)^3-8=0\Rightarrow\left(x-1\right)^3=8\Rightarrow x-1=2\Rightarrow x=3\end{array}\right.\)
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