Zn + 2HCl -> ZnCl2 + H2 (1)
ZnO + 2HCl -> ZnCl2 + H2O (2)
nHCl=0,2.2,5=0,5(mol)
nH2=3,36/22,4=0,15(mol)
Theo PTHH 1 ta có:
nZn=nH2=nZnCl2=0,15(mol)
nHCl=2nH2=0,3(mol)
nHCl(2)=0,5-0,3=0,2(mol)
Theo PTHH 2 ta có:
\(\dfrac{1}{2}\)nHCl=nZnO=nZnCl2=0,1(mol)
a=65.0,15+81.0,1=17,85(g)
mZnCl2=0,25.136=34(g)