Mình trả lời cau a nhé.
a. x−3/5=6-1-2x/3
⇔3(x−3)=6.15−5(1−2x)
Sorry mk trả lời nhầm mk trả lời lại câu a nhé.
a. x−3/5=6-1-2x/3
⇔3(x−3)=6.15−5(1−2x)
Giải các phương trình sau :
a) \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
b) \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
c) \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
d) \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
1,\(\dfrac{5\left(x-1\right)+2}{6}\)-\(\dfrac{7x-1}{4x}\)=\(\dfrac{2\left(2x+1\right)}{7}\)-5
2,\(\dfrac{3\left(x-3\right)}{4}\)+\(\dfrac{4x-10,5}{10}\)=\(\dfrac{3 \left(x+1\right)}{5}\)+6
3,\(\dfrac{2\left(3x+1\right)+1}{4}\)-5=\(\dfrac{2\left(3x-1\right)}{5}\)-\(\dfrac{3x+2}{10}\)
Diễn giải ra cho em với ạ!Em cảm ơn
Giải các phương trình sau:
a, \(\dfrac{3\left(5x-2\right)}{4}-2=\dfrac{7x}{3}-5\left(x-7\right)\)
b, \(\dfrac{x+5}{2}+\dfrac{3-2x}{4}=x-\dfrac{7+x}{6}\)
c, \(\dfrac{x-3}{11}+\dfrac{x+1}{3}=\dfrac{x+7}{9}-1\)
d, \(\dfrac{3x-0,4}{2}+\dfrac{1,5-2x}{3}=\dfrac{x+0,5}{5}\)
c. \(\dfrac{x-4}{5}+\dfrac{3x-2}{10}-x=\dfrac{2x-5}{3}-\dfrac{7x+2}{6}\)
d. \(\left(x+2\right)^3-\left(x-2\right)^3=12x\left(x-1\right)-8\)
e. \(\left(x+5\right)\left(x+2\right)-3\left(4x-3\right)=\left(5-x\right)^2\)
f. \(\dfrac{x-5}{100}+\dfrac{x-4}{101}+\dfrac{x-3}{102}=\dfrac{x-100}{5}+\dfrac{x-101}{4}+\dfrac{x-102}{3}\)
g. \(\dfrac{29-x}{21}+\dfrac{27-x}{23}+\dfrac{25-x}{25}+\dfrac{23-x}{27}+\dfrac{21-x}{29}=5\)
4,\(\dfrac{x+1}{3}\)+\(\dfrac{3\left(2x+1\right)}{4}\)=\(\dfrac{2x+3\left(x+1\right)}{6}\)+\(\dfrac{7+12x}{12}\)
5,\(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\)=4-\(\dfrac{x}{3}\)
6,\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)=1-\(\dfrac{2\left(x-1\right)}{3}\)
\((2x+3)\left(\dfrac{3x+8}{2-7x}+1\right)=(x-5)\left(\dfrac{3x+8}{2-7x}+1\right)\)
Giải các phương trình :
a) \(3x-2=2x-3\)
b) \(3-4u+24+6u=u+27+3u\)
c) \(5-\left(x-6\right)=4\left(3-2x\right)\)
d) \(-6\left(1,5-2x\right)=3\left(-15+2x\right)\)
e) \(0,1-2\left(0,5t-0,1\right)=2\left(t-2,5\right)-0,7\)
f) \(\dfrac{3}{2}\left(x-\dfrac{5}{4}\right)-\dfrac{5}{8}=x\)
Giải pt sau:
a) \(\left(\dfrac{8}{1.9}+\dfrac{8}{9.17}+\dfrac{8}{17.25}+....+\dfrac{8}{49.57}\right)+2.\left(x-1\right)=\dfrac{2x+7}{3}+\dfrac{5x-8}{4}\)
b) \(\left(x+2\right).\left(x-2\right).\left(x^2-10\right)=72\)
c) (x+3)4+ (x+5)4 = 2
\(\dfrac{3x-2}{6}\) -5=\(\dfrac{3-2\left(x+7\right)}{4}\)
