Ta có: (7 – x).( x + 19) = 0
=> 7- x =0
Hoặc: x + 19 = 0
* Nếu: 7- x =0
=> x= 0+7 = 7
* Nếu: x + 19 =0
=> x = 0 - 19 = -19
Vậy: x = 7;-19
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Lời giải
dạng phương trình tích
\(\Leftrightarrow\left[{}\begin{matrix}7-x=0\\x+19=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=7\\x=-19\end{matrix}\right.\)
\(\left[{}\begin{matrix}7-x=0\\x+19=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-7\\x=-19\end{matrix}\right.\)
Vậy...
\(\left(7-x\right)\left(x+19\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}7-x=0\\x+19=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=7\\x=-19\end{matrix}\right.\)
Vậy, \(x\in\left\{-19;7\right\}\)