Bài 3: Phương trình đưa được về dạng ax + b = 0
Các câu hỏi tương tự
a.(x+5)(2x-1)=(2x-3)(x+1)
b.(x+1)(x+9)=(x+3)(x+5)
c.(3x+5)(2x+1)=(6x-2)(x-3)
d.(x-2)(3x+5)=(2x-4)(x+1)
đ.9x2 -1=(3x+1)(2x-3)
e.(2x+5)(x-4)=(x-5)(4-x)
Giải phương trình về dạng ax+b=0
1. (- (x - 3))/2 - 2 = 5(x + 2)/4
2. 2(2x + 1)/5 - (6 + x)/3 = (5 - 4x)/15
3. (7 - 3x)/2 - (5 + x)/5 = 1
4. (x - 1)/2 +3(x + 1)/8 = (11 - 5x)/3
5. (3 + 5x)/5 - 3 = (9x - 3)/4
a) 5x + 6 = 0
b) 9x - 3 = 6x + 21
c) x^3 - 9x = 0
d) 1/x-2 - x^2 -4 /4-x^2= 0
a)5-(x-6)=4(3-2x)
b)2x(x+2)2-8x2=2(x-2)(x2+2x+4)
c)7-(2x+4)=-(x+4)
d)(x-2)3+(3x-1)(3x+1)=(x+1)3
e)(x+1)(2x-3)=(2x-1)(x+5)
f)(x-1)3-x(x+1)2=5x(2-x)-11(x+2)
g)(x-1)-(2x-1)=9-x
h)(x-3)(x+4)-2(3x-2)=(x+4)2
i)x(x+3)2-3x=(x+2)33+11
j)(x+1)(x2-x+1)-2x=x(x+1)(x-1)
tìm m để pt sau có nghiệm luôn dương
a) (3x-2)2 -2m =9x(x-1) -8m
b) \(\dfrac{2x-m}{x-2}\) + \(\dfrac{x-1}{x+2}\) =3
Giải phương trình về dạng ax + b = 0
1. (3x - 2)/3 - 2 = (4x + 1)/4
2. (x - 3)/4 + ( 2x - 1 )/3 = (2 - x)/6
3. 1/2 (x + 1) + 1/4(x + 3) = 3 - 1/3 (x + 2)
4 (x + 4)/5 - x + 4 = x/3 - (x - 2)/2
5. (4 - 5x)/6 = 2 (-x + 1)/2
Giải phương trình về dạng ax + b = 0
1. (3x - 2)/3 - 2 = (4x + 1)/4
2. (x - 3)/4 + ( 2x - 1 )/3 = (2 - x)/6
3. 1/2 (x + 1) + 1/4(x + 3) = 3 - 1/3 (x + 2)
4 (x + 4)/5 - x + 4 = x/3 - (x - 2)/2
5. (4 - 5x)/6 = 2 (-x + 1)/2
bài 2 giải các phương trình sau
b,2(x+3)-4=0
d,5(x-3)=3x-5
f,7(5-x)=11-5x
h,2(3x-1)-3x=10
j,3-2x=3.(x+1)-x-2
m,4(2x-3)-5=6(3-x)-7
Bài 1 : Giải các phương trình sau :
1) (x – 2)(x – 5) (x – 3)(x – 4)
2) ( 6x + 2)(x – 2) 2x(3x – 5)
3) (x – 2) 2 (x – 3)(x + 2)
4) (x–1)(x +3) – (x+2)(x–3) 0
5) (x–2)(x –5) – (x–3)(x–4) 0
6) (3x – 2)(4x + 3) 2x(6x – 1)
7) 4x 2 – (2x + 1)(2x – 1) 0
8) (4x–5)(x+3) (2x – 3)(7+2x)
9) (x + 3)(x – 2) (x + 1) 2
10) (x+7)(x–7) + x 2 – 2 2(x 2 +5)
11) (x–1) 2 + (x+3) 2 2(x– 2)(x+2)
12) (x – 5) 2 (x + 3) 2 + 2
13) (3x + 2) 2 – (3x – 2) 2 5x + 38
Đọc tiếp
Bài 1 : Giải các phương trình sau :
1) (x – 2)(x – 5) = (x – 3)(x – 4)
2) ( 6x + 2)(x – 2) = 2x(3x – 5)
3) (x – 2) 2 = (x – 3)(x + 2)
4) (x–1)(x +3) – (x+2)(x–3) = 0
5) (x–2)(x –5) – (x–3)(x–4) = 0
6) (3x – 2)(4x + 3) = 2x(6x – 1)
7) 4x 2 – (2x + 1)(2x – 1) = 0
8) (4x–5)(x+3) = (2x – 3)(7+2x)
9) (x + 3)(x – 2) = (x + 1) 2
10) (x+7)(x–7) + x 2 – 2 = 2(x 2 +5)
11) (x–1) 2 + (x+3) 2 = 2(x– 2)(x+2)
12) (x – 5) 2 = (x + 3) 2 + 2
13) (3x + 2) 2 – (3x – 2) 2 = 5x + 38