(3x + 1)(3x - 1) = (2x - 1)2 + 5x(x - 2)
⇔ 9x2 - 1 = 4x2 - 4x + 1 + 5x2 - 10x
⇔ -14x = 2
⇔ x = \(-\dfrac{1}{7}\)
(3x + 1)(3x - 1) = (2x - 1)2 + 5x(x - 2)
⇔ 9x2 - 1 = 4x2 - 4x + 1 + 5x2 - 10x
⇔ -14x = 2
⇔ x = \(-\dfrac{1}{7}\)
1) (4x-10)(24+5x) =0
2) 0,5x(x-3)=(x-3)(2,5x-4)
3) 4x2-1=(2x+1)(3x-5)
4) (2-3x)(x+11)=(3x-2)(2-5x)
giải phương trình tícha, 3x-1=0 b, 5x-2=x+4c, 2.(4-2x)-1 =x-3d, 2x-1/3 - x+2/6=3x e, (2x-1).(x.x-6)=0f, (x+2) .(5-4x)=x.x+4x+4
Bài 1: Giải các phương trình tích sau:
2. a) (3x + 2)(x2 –1) = (9x2 – 4)(x + 1) b)x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0
c) 2x(x – 3) + 5(x – 3) = 0 d) (3x – 1)(x2 + 2) = (3x – 1)(7x – 10)
e) (x + 2)(3 – 4x) = x2 + 4x + 4 f) x(2x – 7) – 4x + 14 = 0
g) 3x – 15 = 2x(x – 5) h) (2x + 1)(3x – 2) = (5x – 8)(2x + 1)
i) 0,5x(x – 3) = (x – 3)(1,5x – 1) j) (2x2 + 1)(4x – 3) = (x – 12)(2x2 + 1)
k) x(2x – 9) = 3x(x – 5) l) (x – 1)(5x + 3) = (3x – 8)(x – 1)
a) (x + 2)(3 – 4x) = x2 + 4x + 4
b) x(2x - 7) - 4x + 14 = 0
c) 3x - 15 = 2x(x - 5)
d) (2x + 1)(3x - 2) = (5x - 8)(2x + 1)
I) giải các pt tích:
1) 3x - 12= 5x(x - 4)
2) 3x - 15= 2x(x - 5)
3) 3x(2x - 3) + 2(2x - 3)= 0
4) (4x - 6) (3 - 3x)= 0
a) (4x - 3)\(^2\) - (2x + 1)\(^2\)= 0
b) (3x - 1) (2x - 5)= (3x - 1) (x + 2)
c) (x + 6) (x - 1)= 2(x - 1)
d) (x - 1)\(^2\)= 4
e) 3x - 12= 5x(x - 4)
f) x\(^2\) - 1= 0
Giải phương trình sau:
1) (5x+1)2=(3x-2)2
2) 3x(25x+15)-35(5x+3)=0
3) (x-2)3=(2x+1)3
4) (x-1)(x2+5x-2)-x3+1=0
5) x2+(x+2)(11x-7)=4
giải các phương trình
a) (3x-2)(3x-1) = (3x+1)2
b) (4x-1)(x+1) = (2x-3)2
c) (5x+1)2 = (7x-3)(7x+2)
d) (4-3x)(4+3x)=(9x-3)(1-x)
e) x(x+1)(x+2)(x+3)=24
g) (7x - 2)2= (7x-3)(7x+2)
giải hộ mk vs
1/2x^4+3x^3-x^2+3x+2=0
2/x^4-5x^3+7x^2-5x-16=0
3/(x+2)^4+(x+4)^4=16