\(3x-\left|4x+3\right|=2\)
\(\Leftrightarrow\left|4x+3\right|=3x-2\)
\(\Leftrightarrow\left[{}\begin{matrix}4x+3=3x-2\\4x+3=2-3x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=1\end{matrix}\right.\)
Vậy : \(x\in\left\{-5,1\right\}\)