Phản ứng xảy ra:
\(n_{KClO3}=\frac{24,5}{39+35,5+16.3}=0,2\left(mol\right)\)
\(\Rightarrow n_{KClO2\left(pư\right)}=0,2.70\%=0,14\left(mol\right)\)
\(\Rightarrow n_{Cl2}=0,14.3=0,42\left(mol\right)\)
\(2NaOH+Cl_2\rightarrow NaCl+NaClO\)
\(\Rightarrow n_{NaCl}=n_{NaClO}=n_{Cl2}=0,42\left(mol\right)\)
\(\Rightarrow m=m_{NaCl}+m_{NaClO}=0,42.58,5+0,42.74,5=55,86\left(g\right)\)
6HCl | + |
KClO3 |
→ | 3Cl2 | + | 3H2O | + |
KCl |
-----------0,2----------0,6 mol
Cl2+2NaOH-->NaCl+NaClO+H2O
0,6-----------------0,6-----0,6 mol
nKClO3=24,5\122,5=0,2 mol
=>VCl2=0,6.22,4=13,44 l
=>mChất tan= 0,6.58,5+0,6.74,5=79,8 g