\(=\dfrac{3}{4}.\left(\dfrac{8}{9}+\dfrac{2}{3}\right)=\dfrac{3}{4}.\dfrac{14}{9}=\dfrac{7}{6}\)
\(\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{2}{3}\right)=\dfrac{3}{4}\left(\dfrac{16}{18}+\dfrac{12}{18}\right)=\dfrac{3}{4}\times\dfrac{28}{18}=\dfrac{3}{4}\times\dfrac{14}{9}=\dfrac{7}{6}\)