Question

(2x-1)(3x-4)=2(3x²-5)

Answer 1

(2x-1)(3x-4)=2(3x²-5)

6x²-11x+4 = 6x²-10

14 = 11x

x = 14/11

Answer 2

Ta có: \(\left(2x-1\right)\left(3x-4\right)=2\left(3x^2-5\right)\)

\(\Leftrightarrow6x^2-8x-3x+4=6x^2-10\)

\(\Leftrightarrow-11x+4+10=0\)

\(\Leftrightarrow-11x+14=0\)

\(\Leftrightarrow-11x=-14\)

hay \(x=\dfrac{14}{11}\)

Vậy: \(S=\left\{\dfrac{14}{11}\right\}\)