\(\dfrac{2^{10}\cdot13+2^{10}\cdot65}{2^8\cdot104}=\dfrac{2^{10}\cdot\left(13+65\right)}{2^8\cdot104}=\dfrac{2^{10}\cdot78}{2^8\cdot104}=\dfrac{2^2\cdot3}{4}=3\)
2^10 . ( 13 + 65 ) / 2^8 . 104
2^10 . 78 / 2^8 . 104
= 2^8 . 2^2 . 78 / 2^8 . 104
= 2^2 . 78 / 104
= 4 . 78 / 104
= 78 / 26
= 3
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