\(C_4H_{10} \to C_2H_6 + C_2H_4\\ C_4H_{10} \to CH_4 + C_3H_6\\ C_4H_{10} \to C_4H_{10\ dư}\)
Theo PTHH, ta thấy :
\(2V_{C_4H_{10}\ pư} + V_{C_4H_{10}\ dư} = 1010\\ V_{C_4H_{10}\ pư} + V_{C_4H_{10}\ dư} = 560\\ \Rightarrow V_{C_4H_{10}\ pư} = 450 ; V_{C_4H_{10}\ dư} = 110\\ H = \dfrac{450}{560}.100\% = 80,36\%\)
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