1.
a) 3x + 54 : 2 = 230
3x + 27 = 230
3x = 230 - 27
3x = 203
x = 203: 3
x = \(\frac{203}{3}\)
Vậy x = \(\frac{203}{3}\)
1 ) \(3.x+54:2=230\)
\(3.x+27=230\)
\(3.x=230-27\)
\(3x=203\)
\(x=203:3\)
\(x=\frac{203}{3}\)
b) \(\left(30+\frac{1}{2}+0,5.3-1,5\right):\left(\frac{9}{2}-\frac{7}{2}\right).\left(1,45.x\right)=10\)
\(\left(\frac{61}{2}+1,5-1,5\right):1.\left(1,45.x\right)=10\)
\(30,5:1.\left(1,45.x\right)=10\)
\(30,5.\left(1,45.x\right)=10\)
\(1,45.x=10:30,5\)
\(1,45.x=\frac{20}{61}\)
\(x=\frac{20}{61}:1,45\)
\(x=\frac{400}{1769}\)
Để \(\overline{1996xy}⋮2;5\Rightarrow y=0\)
Thay y = 0 vào ta có: \(\overline{1996x0}\)
Để \(\overline{1996x0⋮}9\Rightarrow1+9+9+6+0+x⋮9\Rightarrow25+x⋮9\Rightarrow25+2⋮9\)
\(\Rightarrow27⋮9\) \(\Rightarrow x=2\)
Thay x= 2,y = 0 vào ta có: \(199620\)
Vậy số cần tìm là: \(199620\)