giả sử có 100g KMnO4, KClO3
⇒m chất rắn =75g
2KMnO4\(\underrightarrow{^{to}}\)K2MnO4+MnO2+O2
x___________x/2_____ x /2__ x/2 (mol)
2KClO3→2KCl+3O2
y _________y___3y/2
\(\left\{{}\begin{matrix}\text{158x+122.5y=100}\\\text{142x+74.5y=75 }\end{matrix}\right.\rightarrow\left\{{}\begin{matrix}\text{x=0.3}\\\text{y=0.4 }\end{matrix}\right.\)
⇒mKMnO4⇒%
⇒mKClO3⇒%