\(1\dfrac{2}{5}x+\dfrac{3}{7}=\dfrac{-4}{5}\)
\(\Rightarrow1\dfrac{2}{5}x=\dfrac{-4}{5}-\dfrac{3}{7}\)
\(\Rightarrow1\dfrac{2}{5}x=\dfrac{-43}{35}\)
\(\Rightarrow x=\dfrac{-43}{35}:1\dfrac{2}{5}\)
\(\Rightarrow\dfrac{-43}{49}\)
Vậy.............
\(1\dfrac{2}{5}x+\dfrac{3}{7}=\dfrac{-4}{5}\)
\(\Leftrightarrow\dfrac{7}{5}x+\dfrac{3}{7}=\dfrac{-4}{5}\)
\(\Leftrightarrow\dfrac{7}{5}x=\dfrac{-4}{5}-\dfrac{3}{7}=\dfrac{-43}{35}\)
\(\Leftrightarrow x=\dfrac{-43}{35}.\dfrac{5}{7}=\dfrac{-43}{49}\)