\(n_{Cl_2}=0,2\left(mol\right);n_{NaBr}=0,5\left(mol\right);n_{NaI}=0,2\left(mol\right)\)
Cl2 + 2I- ---> I2 + 2Cl-
0,1_____0,2_____________0,2
Cl2 + 2Br- ---> Br2 + 2Cl-
0,1______0,2________________0,2
\(\Rightarrow m_{M'}=m_{NaCl}+m_{NaBr}=54,3\left(g\right)\)