\(-\dfrac{15}{12}x+\dfrac{3}{7}=\dfrac{6}{5}x-\dfrac{1}{2}\)<=>\(-\dfrac{5}{4}x+\dfrac{3}{7}=\dfrac{6}{5}x-\dfrac{1}{2}\)
<=>\(\dfrac{3}{7}+\dfrac{1}{2}=\dfrac{6}{5}x+\dfrac{5}{4}x\)<=>\(\dfrac{3}{7}+\dfrac{1}{2}=\left(\dfrac{6}{5}+\dfrac{5}{4}\right)x\)
<=>\(\dfrac{3.2+7}{2.7}=\dfrac{\left(4.6+5.5\right)x}{4.5}\Leftrightarrow x=\dfrac{\left(3.2+7\right).4.5}{2.7\left(4.6+5.5\right)}\)
\(x=\dfrac{\left(3.2+7\right).2.5}{7\left(4.6+5.5\right)}=\dfrac{13.10}{7^3}=\dfrac{130}{243}\)