\(CT:C_nH_{2n+2}\left(1mol\right)\)
\(C_nH_{2n+2}\underrightarrow{t^0,xt}C_nH_{2n}+H_2\)
\(1.......................1...........1\)
\(\overline{M}=\dfrac{14n+2}{2}=7.5\cdot2=15\left(\dfrac{g}{mol}\right)\)
\(\Rightarrow n=2\)
\(\%C=\dfrac{12\cdot2}{12\cdot2+6}\cdot100\%=80\%\)
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