Bài 12 :
\(PTHH:H_2+Cl_2\rightarrow2HCl\)
Ban đầu : 2______3_______
Phứng :2______2__________
Sau phứng :0______1_____4
\(\rightarrow V_{HCl_{thuc.te}}=4.90\%=3,6\left(l\right)\)
Bài 13 :
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)
0,8________________________0,8______
Ta có :
\(n_{MnO2}=\frac{69,6}{55+32}=0,8\left(mol\right)\)
\(n_{Cl2_{thuc.te}}=0,8.70\%=0,56\left(mol\right)\)
\(\rightarrow V_{Cl2}=0,56.22,4=12,544\left(l\right)\)