Ta có:
\(n_{FeCl3}=\frac{16,25}{162,5}=0,1\left(mol\right)\)
Khi cho Cl2 tác dụng với Fe:
\(PTHH:3Cl_2+2Fe\rightarrow2FeCl_3\)
________0,1.3/2 __________ 0,1 (mol)
Điều chế khí Cl2:
\(2KMnO_4+16HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\)
0,15.2/5___0,15.16/5________________0,1.3/2mol
\(\Rightarrow m_{KMnO4}=0,15.\frac{2}{5}.158=9,48\left(g\right)\)
\(\Rightarrow V_{dd\left(HCl\right)}=0,15.\frac{\frac{16}{5}}{1}=0,48\left(l\right)=480\left(ml\right)\)