a, \(\dfrac{1998}{1999}\) < \(\dfrac{1999}{2000}\)
b, \(\dfrac{47}{15}>\dfrac{29}{35}\)
c, \(\dfrac{12}{25}< \) \(\dfrac{25}{49}\)
a, \(\dfrac{1998}{1999}\) < \(\dfrac{1999}{2000}\)
b, \(\dfrac{47}{15}>\dfrac{29}{35}\)
c, \(\dfrac{12}{25}< \) \(\dfrac{25}{49}\)
1 tinh
a,\(5\dfrac{4}{23}.27\dfrac{3}{47}+4\dfrac{3}{47}.\left(-5\dfrac{4}{23}\right)\)
b,4.\(\left(\dfrac{-1}{2}\right)^3+\dfrac{3}{2}\)
c,\(\left(\dfrac{1999}{2011}-\dfrac{2011}{1999}\right)-\left(\dfrac{-12}{1999}-\dfrac{12}{2011}\right)\)
d,\(\left(\dfrac{-5}{11}+\dfrac{7}{22}-\dfrac{-4}{33}-\dfrac{5}{44}\right):\left(\dfrac{381}{22}-39\dfrac{7}{22}\right)\)
So sánh : a, \(\dfrac{29}{60}và\dfrac{15}{28}\) b, \(\dfrac{13}{30}và\dfrac{23}{42}\) c, \(\dfrac{13}{36}và\dfrac{14}{45}\) d, \(\dfrac{1919}{9595}và\dfrac{1111}{5050}\)
\(1\dfrac{13}{15}.0,75-\left(\dfrac{8}{15}+25\%\right).\dfrac{24}{47}-3\dfrac{12}{13}:3\)
1.So Sánh
a) A=\(\dfrac{11}{2017}+\dfrac{4}{2019}và\) B=\(\dfrac{10}{2017}+\dfrac{10}{2019}\)
b) M=\(\dfrac{1}{5}+\dfrac{1}{12}+\dfrac{1}{13}+\dfrac{1}{14}+\dfrac{1}{30}+\dfrac{1}{61}+\dfrac{1}{62}và\dfrac{1}{2}\)
c) E=\(\dfrac{4116-14}{10290-35}và\) K=\(\dfrac{2929-101}{2.1919+404}\)
I tính
1,\(\dfrac{3}{4}.\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}.\dfrac{35}{36}.\dfrac{48}{49}.\dfrac{63}{64}\)
2, 1,2+2,3+......+8,9+9,10+10,11+......+98,99+100,101+......+998,999
3, 1,2+2,4+3,6+4,8+5,10+6,12+....+45,90
4, 1,1+1,11+1,111+......+1,111....11+1,11111....111
(9 số 1) (10 so 1)
Bài tập: So sánh:
a, \(\dfrac{12}{49}\&\dfrac{13}{47}\)
\(b,\dfrac{64}{85}\&\dfrac{17}{35}\)
\(c,\dfrac{19}{31}\&\dfrac{17}{35}\)
(Gợi ý: a,b,c: Phân số chung gian)
\(d,\dfrac{67}{77}\&\dfrac{73}{83}\)
\(e,\dfrac{456}{461}\&\dfrac{123}{128}\)
(Gợi ý: d, e:Phần bù đến đơn vị)
bài 1 so sánh
a) \(\dfrac{45}{105}va\dfrac{84}{147}\)
b) \(\dfrac{-12}{19}va\dfrac{-14}{17}\)
c) \(\dfrac{13}{19}va\dfrac{47}{53}\)
d) \(\dfrac{-29}{38}va\dfrac{-13}{22}\)
a)\(\dfrac{2}{7}+\dfrac{-3}{8}+\dfrac{11}{7}+\dfrac{1}{7}_{ }+\dfrac{5}{-8}\)
b)\(\dfrac{3}{17}+\dfrac{-5}{13}+\dfrac{-18}{35}+\dfrac{14}{17}+\dfrac{17}{-35}_{ }+\dfrac{-8}{13}\)
c)\(\dfrac{-3}{8}+\dfrac{12}{25}+\dfrac{5}{-8}+\dfrac{2}{-5}+\dfrac{13}{25}\)
d)\(\dfrac{-5}{21}+\left(\dfrac{-16}{21}+1\right)\)
e)\(\dfrac{-3}{17}+\left(\dfrac{2}{3}+\dfrac{3}{17}\right)\)
f)\(\left(\dfrac{-1}{6}+\dfrac{5}{-12}\right)+\dfrac{7}{12}\)
So sanh AvaB
A=\(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43},B=\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)