\(\Rightarrow n_{NaOH}=0,2.V;n_{Ba\left(ỌH\right)_2}=0,1.V\Rightarrow n_{OH^-}=0,4V;n_{HCl}=0,03;n_{H2SO4}=0,01;n_{H^+}=0,05\)\(H^++OH^-\rightarrow H_2O\Rightarrow0,4.V=0,05\Rightarrow V=0,125\left(l\right)=125\left(ml\right)\Rightarrow n_{H2O}=0,05\)
BTKL: \(m_A+m_B=m_{M'}+m_{H2O}\Rightarrow m_{M'}=4,3125\left(g\right)\)
---> B