giúp mình nha!!!! cảm ơn mng nhìu ạ ~~~
\(\dfrac{2}{3}+\dfrac{5}{2}-\dfrac{3}{4}=\dfrac{19}{6}-\dfrac{3}{4}=\dfrac{58}{24}=\dfrac{29}{12}\)
\(2:\dfrac{2}{3}-\dfrac{1}{7}=\dfrac{6}{2}-\dfrac{1}{7}=\dfrac{40}{14}=\dfrac{20}{7}\)
\(\dfrac{1}{2}+\dfrac{1}{3}:\dfrac{1}{6}=\dfrac{1}{2}+\left(\dfrac{1}{3}:\dfrac{1}{6}\right)=\dfrac{1}{2}+2=\dfrac{1}{2}+\dfrac{2}{1}=\dfrac{1}{2}+\dfrac{4}{2}=\dfrac{5}{4}\)
\(\dfrac{2}{9}:\dfrac{2}{3}x\dfrac{1}{2}=\dfrac{1}{3}x\dfrac{1}{2}=\dfrac{1}{6}\)
\(2+\dfrac{1}{4}x\dfrac{4}{3}=2+\dfrac{1}{3}=\dfrac{2}{1}+\dfrac{1}{3}=\dfrac{6}{3}+\dfrac{1}{3}=\dfrac{7}{3}\)
\(3x\dfrac{1}{2}x\dfrac{1}{2}=\dfrac{3}{1}x\dfrac{1}{2}x\dfrac{1}{4}=\dfrac{3}{2}x\dfrac{1}{4}=\dfrac{3}{8}\)