\(n_{CO_2}=\dfrac{6.72}{22.4}=0.3\left(mol\right)\)
\(n_{H_2O}=\dfrac{7.2}{18}=0.4\left(mol\right)\)
\(n_{H_2O}>n_{CO_2}\Rightarrow ankan\)
\(CT:C_{\overline{n}}H_{2\overline{n}+2}\)
\(\dfrac{\overline{n}}{2\overline{n}+2}=\dfrac{0.3}{0.4\cdot2}\Rightarrow\overline{n}=3\)
\(\)Hai ankan hơn kém nhau 28 đvc
\(\Rightarrow C_3H_8,CH_4\)
\(\Rightarrow A\)
