Câu trả lời:
= \(\left(x-1\right)\left(x+2\right)\left(x+3\right)\left(x+6\right)=0\)
= \(x+1=0\)
= \(x+2=0\)
= \(x+3=0\)
= \(x+6=0\)
=> x = \(x-1=0\Rightarrow x=1\)
\(x+2=0\Rightarrow x=-2\)
\(x+3=0\Rightarrow x=-3\)
\(x+6=0\Rightarrow x=-6\)
Vậy x = \(1,-2,-3,-6\)