Thay abc=2013 vào P

P= \(\dfrac{abc.a^2bc}{ab+abc.a+abc}\)+\(\dfrac{ab^2c}{bc+b+abc}+\dfrac{abc^2}{ac+c+1}\)

P=\(\dfrac{a^3b^2c^2}{ab\left(1+ac+c\right)}+\dfrac{ab^2c}{b\left(c+1+ac\right)}+\dfrac{abc^2}{ac+c+1}\)

P=\(\dfrac{a^2bc^2}{ac+c+1}+\dfrac{abc}{c+ac+1}+\dfrac{abc^2}{ac+1+c}\)

P=\(\dfrac{a^2bc^2+abc+abc^2}{ac+c+1}\)

P=abc (*)

Thay abc=2013 vào (*)

P=2013

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