\(\frac{G_{hk1}}{K_{hk1}}=\frac{3}{2}\)-> tong so phan la 2+3 =5--> hs kha hk1= \(\frac{2}{5}calop\)

\(\frac{G_{hk2}}{K_{hk2}}=\frac{5}{3}\)-> tong so phan la 5+3=8--> hs kha hk2=\(\frac{3}{8}\) ca lop

HS khá hk1- HS khá hk2=1

\(\frac{2}{5}-\frac{3}{8}=\frac{1}{40}\)( HSca lop)

vay \(\frac{1}{40}.HScalop=1\)

HS cả lớp = 1 : 1/40=40 hs

\(\overrightarrow{u}\left(x_u;y_u;z_u\right)\)

\(x_u=4x_a-\frac{1}{2}x_b+3x_a=11\)

Làm tương tự, tìm được \(\overrightarrow{u}=\left(11;0;\frac{37}{2}\right)\)